Comments on: Validate a username using Javascript and PHP ( AJAX ) http://joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54 FORGET THE NAME, READ THE ARTICLES Thu, 16 Oct 2008 02:09:37 +0000 http://wordpress.org/?v=2.5.1 By: Hi eric http://joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-1015 Hi eric Tue, 07 Oct 2008 14:37:36 +0000 http://www.joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-1015 You're getting this error because when you copy ad paste the code above it changes qutation mark into another completely defferent one. Simple change any double qutations into the one you have in your keyboard. It works fine with me and I've developed it according to my needs. The only problem which this code doesn't deal with is the Middle East charsets!! I'm trying to integrate it with such charsets and if anyone has any idea how to solve this, I would be more than appreciated. Regards, You’re getting this error because when you copy ad paste the code above it changes qutation mark into another completely defferent one. Simple change any double qutations into the one you have in your keyboard.
It works fine with me and I’ve developed it according to my needs. The only problem which this code doesn’t deal with is the Middle East charsets!! I’m trying to integrate it with such charsets and if anyone has any idea how to solve this, I would be more than appreciated.

Regards,

]]> By: eric http://joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-1014 eric Fri, 03 Oct 2008 04:37:45 +0000 http://www.joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-1014 I keep getting Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource any one have any idea why? its refering to this area $query=("Select * from inv_user where userid='$username'"); $result = mysql_query($query); $num = mysql_num_row($result); if ($num > 0) {//Username already exist I keep getting Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource any one have any idea why?

its refering to this area
$query=(”Select * from inv_user where userid=’$username’”);
$result = mysql_query($query);
$num = mysql_num_row($result);
if ($num > 0) {//Username already exist

]]> By: ABC http://joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-997 ABC Fri, 29 Aug 2008 06:20:40 +0000 http://www.joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-997 poor poor

]]> By: Luke70 http://joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-947 Luke70 Mon, 30 Jun 2008 15:15:48 +0000 http://www.joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-947 Very nice scritp, I'll use it with MySQL. I'll let you know. Very nice scritp, I’ll use it with MySQL.
I’ll let you know.

]]> By: hanu http://joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-928 hanu Thu, 29 May 2008 09:37:36 +0000 http://www.joeabiraad.com/ajax/validate-a-username-using-javascript-and-php-ajax/54#comment-928 Its very useful beginners of Ajax Like me... thank u very much.. Its very useful beginners of Ajax Like me… thank u very much..

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